[Mar-2024] Check your preparation for Oracle 1Z0-829 On-Demand Exam
Practice Exam 1Z0-829 Realistic Dumps Verified Questions
NEW QUESTION # 11
Given the code fragments:
Which is true?
- A. The program prints t1 : 1 : t2: 1 : t1 : 2 : t2: 2:
- B. The program prints t1 : 1: t2 : 1: t1 : 1 : t2 : 1 : indefinitely
- C. The program prints an exception
- D. The program prints t1 : 1: t2 : 1: t1 : t2 : 2 : in random order.
Answer: A
Explanation:
Explanation
The code creates two threads, t1 and t2, and starts them. The threads will print their names and the value of the Atomic Integer object, x, which is initially set to 1. The threads will then increment the value of x and print their names and the new value of x. Since the threads are started at the same time, the output will be in random order. However, the final output will always be t1 : 1 : t2: 1 : t1 : 2 : t2: 2: References: AtomicInteger (Java SE
17 & JDK 17) - Oracle
NEW QUESTION # 12
Given the code fragment:
Which action enables the code to compile?
- A. Make the regNo variable public
- B. Make the regNo variable static.
- C. Remove the regNO initialization statement.
- D. Replace thye regNo variable static
- E. Replace record with void.
Answer: A
Explanation:
The code will compile if the regNo variable is made public. This is because the regNo variable is being accessed in the main method of the App class, which is outside the scope of the Product class. Making the regNo variable public will allow it to be accessed from outside the class. Reference: https://education.oracle.com/products/trackp_OCPJSE17, https://mylearn.oracle.com/ou/learning-path/java-se-17-developer/99487, https://docs.oracle.com/javase/tutorial/java/javaOO/accesscontrol.html
NEW QUESTION # 13
Which statement is true?
- A. The lock () method returns a boolean indicator immediately if it has managed to acquire the lock, otherwise it waits for the lock acquisition.
- B. The Lock () method returns a boolean indicator immediately regardless if it has or has not managed to acquire the lock
- C. The tryLock () method returns a boolean indicator immediately regardless if it has or has not managed to acquire the lock.
- D. The tryLock () method returns a boolean indicator immediately if it has managed to acquire the lock, otherwise it waits for the lock acquisition.
Answer: C
Explanation:
Explanation
The tryLock () method of the Lock interface is a non-blocking attempt to acquire a lock. It returns true if the lock is available and acquired by the current thread, and false otherwise. It does not wait for the lock to be released by another thread. This is different from the lock () method, which blocks the current thread until the lock is acquired, and does not return any value. References:
https://docs.oracle.com/en/java/javase/17/docs/api/java.base/java/util/concurrent/locks/Lock.html#tryLock(), 3, 4
NEW QUESTION # 14
Given:
What is the result?
- A. UserName
- B. User name (US)
- C. User name (EN)
- D. The program throws a MissingResourceException.
- E. User name (EN - US)
Answer: D
Explanation:
Explanation
The answer is B because the code fragment contains a logical error that causes a MissingResourceException at runtime. The code fragment tries to load a resource bundle with the base name "Captions.properties" and the locale "en_US". However, there is no such resource bundle available in the classpath. The available resource bundles are:
Captions.properties
Captions_en.properties
Captions_US.properties
Captions_en_US.properties
The ResourceBundle class follows a fallback mechanism to find the best matching resource bundle for a given locale. It first tries to find the resource bundle with the exact locale, then it tries to find the resource bundle with the same language and script, then it tries to find the resource bundle with the same language, and finally it tries to find the default resource bundle with no locale. If none of these resource bundles are found, it throws a MissingResourceException.
In this case, the code fragment is looking for a resource bundle with the base name "Captions.properties" and the locale "en_US". The ResourceBundle class will try to find the following resource bundles in order:
Captions.properties_en_US
Captions.properties_en
Captions.properties
However, none of these resource bundles exist in the classpath. Therefore, the ResourceBundle class will throw a MissingResourceException.
To fix this error, the code fragment should use the correct base name of the resource bundle family, which is
"Captions" without the ".properties" extension. For example:
ResourceBundle captions = ResourceBundle.getBundle("Captions", currentLocale); This will load the appropriate resource bundle for the current locale, which is "Captions_en_US.properties" in this case. References:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
ResourceBundle (Java Platform SE 8 )
About the ResourceBundle Class (The Java™ Tutorials > Internationalization)
NEW QUESTION # 15
Given the code fragment:
What is the result?
- A. 0
- B. 1
- C. 2
- D. 3
- E. 4
- F. 5
Answer: D
Explanation:
The code fragment is creating a string variable "a" with the value "Hello! Java". Then, it is printing the index of "Java" in "a". Next, it is replacing "Hello!" with "Welcome!" in "a". Then, it is printing the index of "Java" in "a". Finally, it is creating a new StringBuilder object "b" with the value of "a" and printing the index of "Java" in "b". The output will be 8109 because the index of "Java" in "a" is 8, the index of "Java" in "a" after replacing "Hello!" with "Welcome!" is 10, and the index of "Java" in "b" is 9. Reference: Oracle Java SE 17 Developer source and documents: [String (Java SE 17 & JDK 17)], [StringBuilder (Java SE 17 & JDK 17)]
NEW QUESTION # 16
Given the code fragment:
What is the result?
- A. false 1
false 2 - B. false 1
ture 2 - C. falase 0
true 1 - D. true 1
false 2
Answer: D
Explanation:
Explanation
The code fragment is comparing the values of a, b, and c using the < and > operators. The first comparison, d, is checking if a is less than b and greater than c. Since a is equal to 2, b is equal to -2, and c is equal to -4, this comparison will evaluate to true. The second comparison, e, is checking if a is greater than b and a is greater than c. Since a is equal to 2, b is equal to -2, and c is equal to -4, this comparison will evaluate to false.
Therefore, the result will be true 1 false 2. References: Operators (The Java™ Tutorials > Learning the Java Language - Oracle
NEW QUESTION # 17
Given the code fragment:
What is the result?
- A. PT5SPTIMP6D
- B. $SIM6D
- C. PT5000PT60MP6D
- D. 5000$60M6D
Answer: C
Explanation:
The code fragment is creating a Duration object with a value of 5000 milliseconds, then printing it. Then, it is creating another Duration object with a value of 60 seconds, then printing it. Finally, it is creating a Period object with a value of 6 days, then printing it. The output will be "PT5000PT60MP6D". Reference: https://docs.oracle.com/javase/8/docs/api/java/time/Duration.html, https://docs.oracle.com/javase/8/docs/api/java/time/Period.html
NEW QUESTION # 18
Given:
What is the result?
- A. Software game write error
- B. Software Game Software Game Chese 2
- C. Software Game Chess 2
- D. Software Game read error
- E. Software Game Chess 0
- F. Software Game Software Game chess 0
Answer: B
Explanation:
Explanation
The answer is B because the code uses the writeObject and readObject methods of the ObjectOutputStream and ObjectInputStream classes to serialize and deserialize the Game object. These methods use the default serialization mechanism, which writes and reads the state of the object's fields, including the inherited ones. Therefore, the title field of the Software class is also serialized and deserialized along with the players field of the Game class. The toString method of the Game class calls the toString method of the Software class using super.toString(), which returns the value of the title field.
Hence, when the deserialized object is printed, it shows "Software Game Software Game Chess 2".
References:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Serialization and Deserialization in Java with Example
NEW QUESTION # 19
Given:
What is the result?
- A. D D D
- B. B A D
- C. D A D
- D. B A C
Answer: B
Explanation:
Explanation
The answer is C because the code demonstrates the concept of method overloading and type conversion in Java. Method overloading allows different methods to have the same name but different parameters. Type conversion allows values of one data type to be assigned to another data type, either automatically or explicitly. In the code, the class Test has four methods named sum, each with different parameter types: int, float, and double. The main method creates an instance of Test and calls the sum method with different arguments. The compiler will choose the most specific method that matches the arguments, based on the following rules:
If there is an exact match between the argument types and the parameter types, that method is chosen.
If there is no exact match, but there is a method with compatible parameter types, that method is chosen.
Compatible types are those that can be converted from one to another automatically, such as int to long or float to double.
If there is more than one method with compatible parameter types, the most specific method is chosen.
The most specific method is the one whose parameter types are closest to the argument types in terms of size or precision.
In the code, the following method calls are made:
test.sum(10, 10.5) -> This matches the sum(int a, float b) method exactly, so it is chosen.
The result is 20.5, which is converted to int and printed as 20 (B).
test.sum(10) -> This does not match any method exactly, but it matches the sum(double a) method with compatible types, as int can be converted to double automatically. The result is 10.0, which is printed as 10
(A). test.sum(10.5, 10) -> This does not match any method exactly, but it matches two methods with compatible types: sum(float a, float b) and sum(double a, double b). The latter is more specific, as double is closer to the argument types than float. The result is 20.5, which is printed as 20 (D).
Therefore, the output is B A D. References
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Method Overloading in Java
Type conversion in Java with Examples
Java Method Overloading with automatic type conversions
NEW QUESTION # 20
Given the code fragment:
What is the result?
- A. A NullPointerException is thrown
Cat
Cat - B. Cat
null - C. Dog
Dog - D. Cat
Dog
Answer: B
Explanation:
The answer is E because the code fragment creates a new Pet object with the name "Dog" and assigns it to the variable p. Then, it assigns p to p1. Next, it changes the name of p1 to "Cat". Then, it assigns p1 to p. Finally, it sets p to null and prints the name of p and p1. The output will be "Cat" and "null" because p is set to null and p1 still points to the Pet object with the name "Cat".
NEW QUESTION # 21
Given the code fragment:
What is the result?
- A. falase 0
true 1 - B. false 1
false 2 - C. false 1
ture 2 - D. true 1
false 2
Answer: A
Explanation:
The code fragment is comparing the values of a, b, and c using the < and > operators. The first comparison, d, is checking if a is less than b and greater than c. Since a is equal to 2, b is equal to -2, and c is equal to -4, this comparison will evaluate to true. The second comparison, e, is checking if a is greater than b and a is greater than c. Since a is equal to 2, b is equal to -2, and c is equal to -4, this comparison will evaluate to false. Therefore, the result will be true 1 false 2. Reference: Operators (The Java™ Tutorials > Learning the Java Language - Oracle
NEW QUESTION # 22
Given the code fragment:
abstract sealed interface SInt permits Story, Art { default String getTitle() { return "Book Title" ; }
}
Which set of class definitions compiles?
- A. Interace story extends STnt {}
Interface Art extends SInt {} - B. Non-sealed interface story extends SInt {}
Non-sealed interaface Art extends Sint {} - C. Public interface story extends sInd {}
Public interface Art extends SInt {} - D. Sealed interface Storty extends sInt {}
Non-sealed class Art implements Sint {} - E. Non-sealed interface story extends SInt {}
Class Art implements Sint {}
Answer: D
Explanation:
The answer is C because the code fragment given is an abstract sealed interface SInt that permits Story and Art. The correct answer is option C, which is a sealed interface Story that extends SInt and a non-sealed class Art that implements SInt. This is because a sealed interface can only be extended by the classes or interfaces that it permits, and a non-sealed class can implement a sealed interface.
Option A is incorrect because interface is misspelled as interace, and Story and Art should be capitalized as they are the names of the permitted classes or interfaces.
Option B is incorrect because public is misspelled as public, and sInd should be SInt as it is the name of the sealed interface.
Option D is incorrect because a non-sealed interface cannot extend a sealed interface, as it would violate the restriction of permitted subtypes.
Option E is incorrect because both Story and Art cannot be non-sealed interfaces, as they would also violate the restriction of permitted subtypes.
Reference:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Sealed Classes and Interfaces in Java 15 | Baeldung
Sealed Class in Java - Javatpoint
NEW QUESTION # 23
Given the code fragment:
Which two statements at Line nl independently enable you to print 1250?
- A. Integer res = 250 + s:
- B. Integer res= 250 + s2;
- C. Integer res = 250 + integer.parseint (s)
- D. Integer res = 250 + integer (s2):
- E. Integer res = 250 + integer . valueof (s);
- F. Integer res = 250; Res = + s2;
Answer: C,E
Explanation:
Explanation
The code fragment is creating a string variable "s" with the value "10_00" and an integer variable "s2" with the value 10. The string "s" is using an underscore as a separator for readability, which is allowed in Java SE
171. The question is asking for two statements that can add 250 to the numeric value of "s" and assign it to an integer variable "res". The correct answers are A and E because they use the methods parseInt and valueOf of the Integer class to convert the string "s" to an integer. Both methods interpret the string as a signed decimal integer and return the equivalent int or Integer value23. The other options are incorrect because they either use invalid syntax, such as B and C, or they do not convert the string "s" to an integer, such as D and F: References: Binary Literals (The Java™ Tutorials > Learning the Java Language > Numbers and Strings), Integer (Java SE 17 & JDK 17), Integer (Java SE 17 & JDK 17)
NEW QUESTION # 24
Given:
Which statement is true?
- A. The program throws outofStockException.
- B. The program throws ClassCastException
- C. The program fails to compile.
- D. The program throws StockException.
Answer: C
Explanation:
The answer is B because the code fragment contains a syntax error that prevents it from compiling. The code fragment tries to catch a StockException in line 10, but the catch block does not have a parameter of type StockException. The catch block should have a parameter of type StockException, such as:
catch (StockException e) { // handle the exception }
This is required by the Java syntax for the catch clause, which must have a parameter that is a subclass of Throwable. Without a parameter, the catch block is invalid and causes a compilation error.
Option A is incorrect because the program does not throw a StockException, as it does not compile.
Option C is incorrect because the program does not throw an OutofStockException, as it does not compile.
Option D is incorrect because the program does not throw a ClassCastException, as it does not compile. Reference:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
The try-with-resources Statement (The Java™ Tutorials > Essential Classes > Exceptions) The catch Blocks (The Java™ Tutorials > Essential Classes > Exceptions)
NEW QUESTION # 25
Which two code fragments compile?
- A.
- B.
- C.
- D.
- E.
Answer: B,D
Explanation:
The two code fragments that compile are B and E. These are the only ones that use the correct syntax for declaring and initializing a var variable. The var keyword is a reserved type name that allows the compiler to infer the type of the variable based on the initializer expression. However, the var variable must have an initializer, and the initializer must not be null or a lambda expression. Therefore, option A is invalid because it does not have an initializer, option C is invalid because it has a null initializer, and option D is invalid because it has a lambda expression as an initializer. Option B is valid because it has a String initializer, and option E is valid because it has an int initializer.
https://docs.oracle.com/en/java/javase/17/language/local-variable-type-inference.html
NEW QUESTION # 26
Given the code fragment:
What is the result?
- A. Range1
Note a valid rank. - B. Range 1
Range 2
Range 3
Range 1
Not a valida rank - C. Range 1
Range 2
Range 3 - D. Range 1
Answer: B
Explanation:
The code fragment is using the switch statement with the new Java 17 syntax. The switch statement checks the value of the variable rank and executes the corresponding case statement. In this case, the value of rank is 4, so the first case statement is executed, printing "Range1". The second and third case statements are also executed, printing "Range2" and "Range3". The default case statement is also executed, printing "Not a valid rank". Reference: Java Language Changes - Oracle Help Center
NEW QUESTION # 27
Given the course table:
Given the code fragment:
- A. 0
- B. false
- C. 1
- D. true
Answer: D
Explanation:
The code fragment will execute the update statement and set the course fee of the course with ID 1021 to 5000. The executeUpdate method returns an int value that indicates the number of rows affected by the SQL statement. In this case, only one row will be updated, so the result variable will be 1. The if statement will check if the result is greater than 0, which is true, and print "Updated successfully". Therefore, the output of the code fragment is true. Reference: https://education.oracle.com/products/trackp_OCPJSE17, https://mylearn.oracle.com/ou/learning-path/java-se-17-developer/99487, https://docs.oracle.com/en/java/javase/17/docs/api/java.sql/java/sql/Statement.html#executeUpdate(java.lang.String)
NEW QUESTION # 28
Given:
What is the result
- A. UnDefined
- B. Marketing
- C. Marketing
Finance
Technical - D. Marketing
Undefined
Answer: A
Explanation:
Explanation
The code fragment is using the switch statement with the new Java 17 syntax. The switch statement checks the value of the variable desig and executes the corresponding case statement. In this case, the value of desig is
"CTO", which does not match any of the case labels. Therefore, the default case statement is executed, which prints "Undefined". The other case statements are not executed, because there is no fall through in the new syntax. Therefore, the output of the code fragment is:
Undefined
NEW QUESTION # 29
Given:
What is the result?
- A. Compilation fails
- B. A RuntimeException is thrown
- C. Tablechair Tablechair
- D. wTableChair TableChair
- E. Wtablechair tableChair
Answer: A
Explanation:
Explanation
The code fragment will fail to compile because the class name and the constructor name do not match. The class name is Furniture, but the constructor name is Wtable. This will cause a syntax error. The correct way to define a constructor is to use the same name as the class name. Therefore, the code fragment should change the constructor name to Furniture or change the class name to Wtable.
NEW QUESTION # 30
Given:
Which two should the module-info file include for it to represent the service provider interface?
- A. exports com.transport.vehicle.cars.Car;
- B. Exports com.transport.vehicle;
- C. Exports com.transport.vehicle.cars;
- D. Requires cm.transport.vehicle,cars:
- E. Provides.com.transport.vehicle.cars.Car with com.transport.vehicle.cars. impt, CatImpI;
- F. Provides.com.transport.vehicle.cars.Car impl,CarImp1 to com.transport.vehicle.cars. Cars
- G. Requires cm.transport.vehicle,cars:
Answer: A,E
Explanation:
The answer is B and E because the module-info file should include a provides directive and an exports directive to represent the service provider interface. The provides directive declares that the module provides an implementation of a service interface, which is com.transport.vehicle.cars.Car in this case. The with clause specifies the fully qualified name of the service provider class, which is com.transport.vehicle.cars.impl.CarImpl in this case. The exports directive declares that the module exports a package, which is com.transport.vehicle.cars in this case, to make it available to other modules. The package contains the service interface that other modules can use.
Option A is incorrect because requires is not the correct keyword to declare a service provider interface. Requires declares that the module depends on another module, which is not the case here.
Option C is incorrect because it has a typo in the module name. It should be com.transport.vehicle.cars, not cm.transport.vehicle.cars.
Option D is incorrect because it has a typo in the keyword provides. It should be provides, not Provides. It also has a typo in the service interface name. It should be com.transport.vehicle.cars.Car, not com.transport.vehicle.cars.Car impl. It also has an unnecessary to clause, which is used to limit the accessibility of an exported package to specific modules.
Option F is incorrect because it exports the wrong package. It should export com.transport.vehicle.cars, not com.transport.vehicle.cars.impl. The impl package contains the service provider class, which should not be exposed to other modules.
Option G is incorrect because it exports the wrong package. It should export com.transport.vehicle.cars, not com.transport.vehicle. The vehicle package does not contain the service interface or the service provider class. Reference:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Java Modules - Service Interface Module - GeeksforGeeks
Java Service Provider Interface | Baeldung
NEW QUESTION # 31
Given the code fragment:
Which code line n1, obtains the java.io.Console object?
- A.
- B.
- C.
- D.
- E.
Answer: D
Explanation:
The code fragment is trying to obtain the java.io.Console object, which is a class that provides methods to access the character-based console device, if any, associated with the current Java virtual machine. The correct way to obtain the Console object is to call the static method Console console() in the java.lang.System class. This method returns the unique Console object associated with the current Java virtual machine, if any. Therefore, option A is correct, as it calls System.console() and assigns it to a Console variable. Reference:
https://docs.oracle.com/javase/17/docs/api/java.base/java/io/Console.html
https://docs.oracle.com/javase/17/docs/api/java.base/java/lang/System.html#console()
https://education.oracle.com/products/trackp_OCPJSE17
https://mylearn.oracle.com/ou/learning-path/java-se-17-developer/99487
NEW QUESTION # 32
Given:
What is the result?
- A. 1001
1001
1000 - B. 101
101
1000 - C. 1001
100
1000 - D. 100
100
1000
Answer: C
Explanation:
The code fragment is using the bitwise operators & (AND), | (OR), and ^ (XOR) to perform operations on the binary representations of the integer values. The & operator returns a 1 in each bit position where both operands have a 1, the | operator returns a 1 in each bit position where either operand has a 1, and the ^ operator returns a 1 in each bit position where only one operand has a 1. The binary representations of the integer values are as follows:
1000 = 1111101000
100 = 1100100
101 = 1100101
The code fragment performs the following operations:
x = x ^ y; // x becomes 1111010101, which is 1001 in decimal
y = x ^ y; // y becomes 1100100, which is 100 in decimal
x = x ^ y; // x becomes 1100101, which is 101 in decimal
The code fragment then prints out the values of x, y, and z, which are 1001, 100, and 1000 respectively. Therefore, option D is correct.
NEW QUESTION # 33
Given the code fragments:
Which action prints Wagon : 200?
- A. At Line n1, implement the java.io.AutoCloseable interface
- B. At line n2, in the main method signature, add throws IOException, ClassCastException.
- C. At line n1, implement the java.io, Serializable interface.
- D. At Line n3, replace Car with LuxurayCar.
- E. At line n2, in the main method signature, add throws IoException, ClassNotFoundException.
- F. At line n3, replace readObject (0 with readLine().
Answer: E
Explanation:
The code fragment is trying to read an object from a file using the ObjectInputStream class. This class throws an IOException and a ClassNotFoundException. To handle these exceptions, the main method signature should declare that it throws these exceptions. Otherwise, the code will not compile. If the main method throws these exceptions, the code will print Wagon : 200, which is the result of calling the toString method of the LuxuryCar object that was written to the file. Reference: ObjectInputStream (Java SE 17 & JDK 17) - Oracle, ObjectOutputStream (Java SE 17 & JDK 17) - Oracle
NEW QUESTION # 34
Given the directory structure:
Given the definition of the Doc class:
Which two are valid definition of the wordDoc class?
- A. Package p1;
Public class wordDoc extends Doc () - B. Package p1,
non-sealed abstract class WordDoc extends Doc () - C. Package p1;
Public non-sealed class wordDoc extends Doc () - D. Package p1;
Public final class WordDoc extends Doc () - E. Package p1, p2;
Public non-sealed class WordDoc extends Doc () - F. Package p1, p2;
Public sealed class WordDoc extends Doc ()
Answer: C,D
Explanation:
The correct answer is A and F because the wordDoc class must be a non-sealed class or a final class to extend the sealed Doc class. Option B is incorrect because the wordDoc class must be non-sealed or final. Option C is incorrect because the wordDoc class cannot be in a different package than the Doc class. Option D is incorrect because the wordDoc class cannot be a sealed class. Option E is incorrect because the wordDoc class cannot be an abstract class. Reference: Oracle Certified Professional: Java SE 17 Developer, 3 Sealed Classes - Oracle Help Center
NEW QUESTION # 35
Which statement is true?
- A. A thread in waiting state must handle InterrupedException.
- B. After the timed wait expires, the waited thread moves to the terminated state.
- C. thread in waiting state consumes CPU cycles.
- D. IllegalStateException is thrown if a thread in waiting state is moved back to runnable.
Answer: A
Explanation:
A thread in waiting state is waiting for another thread to perform a particular action, such as calling notify() or notifyAll() on a shared object, or terminating a joined thread. A thread in waiting state can be interrupted by another thread, which will cause the waiting thread to throw an InterruptedException and return to the runnable state. Therefore, a thread in waiting state must handle InterruptedException, either by catching it or declaring it in the throws clause. Reference: Thread.State (Java SE 17 & JDK 17), [Thread (Java SE 17 & JDK 17)]
NEW QUESTION # 36
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Valid 1Z0-829 Dumps for Helping Passing Oracle Exam: https://actualtests.troytecdumps.com/1Z0-829-troytec-exam-dumps.html